American Binomial Model in Python

Having written about pricing American-style options on a binomial tree in q, I thought it would be instructive to do the same in Python and NumPy. Here is the code:

import functools as ft
import numpy as np

def BPTree(n, S, u, d):
  r = [np.array([S])]
  for i in range(n):
    r.append(np.concatenate((r[-1][:1]*u, r[-1]*d)))
  return r

def GBM(R, P, S, T, r, b, v, n):
  t = float(T)/n
  u = np.exp(v * np.sqrt(t))
  d = 1./u
  p = (np.exp(b * t) - d)/(u - d)
  ptree = BPTree(n, S, u, d)[::-1]
  R_ = ft.partial(R, np.exp(-r*t), p)
  return reduce(R_, map(P, ptree))[0]

def American(D, p, a, b): return np.maximum(b, D*(a[:-1]*p + a[1:]*(1-p)))
def VP(S, K): return np.maximum(K - S, 0)
ABM = ft.partial(GBM, American)

There is a minor deviation from the q code: we are allowing d to be specified in BPTree. But otherwise, they are doing the same thing. Performance (as measured in ipython) isn’t too far-off either:

In [1]: from binomial import *
In [2]: %timeit ABM(ft.partial(VP,K=102.0), 100.0, 1.0, 0.08, 0.08, 0.2, 1000)
10 loops, best of 3: 38.4 ms per loop
In [3]: ABM(ft.partial(VP,K=102.0), 100.0, 1.0, 0.08, 0.08, 0.2, 1000)
Out[3]: 6.2215001602514555

Note the similarity between the q and Python code. The similarity is a result of using NumPy and functools which enabled Python to perform array-oriented computation and partial function application. We did use a loop in BPTree as Python/NumPy does not seem to have the same “scan” operation as q. I suppose we could have created a numpy.ufunc to use accumulate()… but the loop felt cleaner and more Pythonic.

European Binomial Model in q and Python

In the previous post, we created a binomial probability mass function (pmf). We can use that to easily evaluate European-style options:

EBM:{[P;S;K;T;r;b;v;n]                 / European Binomial Model (CRR)
 t:T%n;                                / time interval
 u:exp v*sqrt t;                       / up
 d:1%u;                                / down
 p:(exp[b*t]-d)%(u-d);                 / probability of up
 ns:til n+1;                           / 0, 1, 2, ..., n
 us:u xexp ns;                         / u**0, u**1, ...
 ds:d xexp ns;                         / d**0, d**1, ...
 Ss:S*ds*reverse us;                   / prices at tree leaves
 ps:pmf[n;p];                          / probabilities at tree leaves
 exp[neg r*T]*sum P[Ss;K]*ps }

Note that P is the payoff, S is the current price, K is the strike price, T is the time to maturity, r is the risk-free rate, v is the volatility, b is the cost of carry and n is the depth of the binomial tree. The Python version using NumPy and SciPy actually looks quite similar:

def EuropeanBinomialModel(P, S, K, T, r, b, v, n):
  n = int(n)
  t = float(T)/n                              # time interval
  u = np.exp(v * np.sqrt(t))                  # up
  d = 1/u                                     # down
  p = (np.exp(b*t)-d)/(u-d)                   # probability of up
  ns = np.arange(0, n+1, 1)                   # 0, 1, 2, ..., n
  us = u**ns                                  # u**0, u**1, ...
  ds = d**ns                                  # d**0, d**1, ...
  Ss = S*us*ds[::-1]                          # prices at leaves
  ps = binom_pmf(ns, n, p)                    # probabilities at leaves
  return np.exp(-r*T) * np.sum(P(Ss,K) * ps)

As we can see, both code has no explicit loops. This is possible in Python as NumPy and SciPy are array-oriented. NumPy and SciPy’s idea of “broadcasting” has some similarity with k/q’s concept of “atomic functions” (definition: a function f of any number of arguments is atomic if f is identical to f’).